0=18d^2-54d+28

Solution for 0=18d^2-54d+28 equation:

0=18d^2-54d+28

We move all terms to the left:

0-(18d^2-54d+28)=0

We add all the numbers together, and all the variables

-(18d^2-54d+28)=0

We get rid of parentheses

-18d^2+54d-28=0

a = -18; b = 54; c = -28;
Δ = b2-4ac
Δ = 542-4·(-18)·(-28)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-30}{2*-18}=\frac{-84}{-36}
=2+1/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+30}{2*-18}=\frac{-24}{-36}
=2/3
$